2x^2+40=4x^2

Solution for 2x^2+40=4x^2 equation:

Simplifying
2x2 + 40 = 4x2

Reorder the terms:
40 + 2x2 = 4x2

Solving
40 + 2x2 = 4x2

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-4x2' to each side of the equation.
40 + 2x2 + -4x2 = 4x2 + -4x2

Combine like terms: 2x2 + -4x2 = -2x2
40 + -2x2 = 4x2 + -4x2

Combine like terms: 4x2 + -4x2 = 0
40 + -2x2 = 0

Add '-40' to each side of the equation.
40 + -40 + -2x2 = 0 + -40

Combine like terms: 40 + -40 = 0
0 + -2x2 = 0 + -40
-2x2 = 0 + -40

Combine like terms: 0 + -40 = -40
-2x2 = -40

Divide each side by '-2'.
x2 = 20

Simplifying
x2 = 20

Take the square root of each side:
x = {-4.472135955, 4.472135955}